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    <title>topic Re: find value from matrix in Mathcad</title>
    <link>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934147#M210582</link>
    <description>&lt;P&gt;&lt;span class="lia-inline-image-display-wrapper lia-image-align-inline" image-alt="image.png" style="width: 999px;"&gt;&lt;img src="https://www.ptcusercommunity.com/t5/image/serverpage/image-id/99402iF86E49DE506C85C3/image-size/large?v=v2&amp;amp;px=999" role="button" title="image.png" alt="image.png" /&gt;&lt;/span&gt;&lt;/P&gt;</description>
    <pubDate>Sun, 03 Mar 2024 01:57:33 GMT</pubDate>
    <dc:creator>ttokoro</dc:creator>
    <dc:date>2024-03-03T01:57:33Z</dc:date>
    <item>
      <title>find value from matrix</title>
      <link>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934086#M210553</link>
      <description>&lt;P&gt;need to find q1 which is basically the values of qcza( known variable) qcza is the resistance in known depth [z].&amp;nbsp;&lt;/P&gt;&lt;P&gt;q1 is equal to qcza when the depth is between 0.7D&amp;lt;z&amp;lt; 4D when D=0.4 and it has always to choose the minimum value until there is smaller value. the file is attached&lt;/P&gt;&lt;P&gt;&lt;span class="lia-inline-image-display-wrapper lia-image-align-inline" image-alt="2024-03-02 (2).png" style="width: 400px;"&gt;&lt;img src="https://www.ptcusercommunity.com/t5/image/serverpage/image-id/99376iDA5E59743E5BF7FC/image-size/medium?v=v2&amp;amp;px=400" role="button" title="2024-03-02 (2).png" alt="2024-03-02 (2).png" /&gt;&lt;/span&gt;&lt;/P&gt;&lt;P&gt; &lt;/P&gt;</description>
      <pubDate>Sat, 02 Mar 2024 08:54:17 GMT</pubDate>
      <guid>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934086#M210553</guid>
      <dc:creator>YA_10963798</dc:creator>
      <dc:date>2024-03-02T08:54:17Z</dc:date>
    </item>
    <item>
      <title>Re: find value from matrix</title>
      <link>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934106#M210559</link>
      <description>&lt;P&gt;Its not perfectly clear to me what you are looking for.&lt;/P&gt;
&lt;P&gt;As I understood:&lt;/P&gt;
&lt;P&gt;1) Input value is a length D (in your example 0.4 m)&lt;/P&gt;
&lt;P&gt;2) a range is calculated running from 0.7*D up to 4*D (in your example 0.28 m up to 1,6 m)&lt;/P&gt;
&lt;P&gt;3) We look up all the q-values corrsponding to the range calculated in #2 and select the smallest of them&lt;/P&gt;
&lt;P&gt;In your example the output would be 2.22 MPa (which by chance happens to be at the upper end of the interval. Is this correct?&lt;/P&gt;
&lt;P&gt;Or should we chose the q-value corresponding to the smallest z-value (-&amp;gt; 5.721 MPa, first value in interval)?&lt;/P&gt;
&lt;P&gt;OR ...?&lt;/P&gt;
&lt;P&gt;BTW, your data looks a bit ... erratic, doesn't it?&lt;/P&gt;
&lt;P&gt;&lt;span class="lia-inline-image-display-wrapper lia-image-align-inline" image-alt="Werner_E_3-1709380726047.png" style="width: 400px;"&gt;&lt;img src="https://www.ptcusercommunity.com/t5/image/serverpage/image-id/99390i4098FE2D680AFC35/image-size/medium?v=v2&amp;amp;px=400" role="button" title="Werner_E_3-1709380726047.png" alt="Werner_E_3-1709380726047.png" /&gt;&lt;/span&gt;&lt;span class="lia-inline-image-display-wrapper lia-image-align-inline" image-alt="Werner_E_4-1709380735448.png" style="width: 400px;"&gt;&lt;img src="https://www.ptcusercommunity.com/t5/image/serverpage/image-id/99391iBA8E0F4943352912/image-size/medium?v=v2&amp;amp;px=400" role="button" title="Werner_E_4-1709380735448.png" alt="Werner_E_4-1709380735448.png" /&gt;&lt;/span&gt;&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;Here is how I would implement the algorithm described above - as a function with D as input and the q-value as output.&lt;/P&gt;
&lt;P&gt;&lt;span class="lia-inline-image-display-wrapper lia-image-align-inline" image-alt="Werner_E_0-1709383316588.png" style="width: 506px;"&gt;&lt;img src="https://www.ptcusercommunity.com/t5/image/serverpage/image-id/99392i43049FAFA3943BE4/image-dimensions/506x419?v=v2" width="506" height="419" role="button" title="Werner_E_0-1709383316588.png" alt="Werner_E_0-1709383316588.png" /&gt;&lt;/span&gt;&lt;/P&gt;
&lt;P&gt;Prime 9 worksheet attached&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;</description>
      <pubDate>Sat, 02 Mar 2024 12:42:50 GMT</pubDate>
      <guid>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934106#M210559</guid>
      <dc:creator>Werner_E</dc:creator>
      <dc:date>2024-03-02T12:42:50Z</dc:date>
    </item>
    <item>
      <title>Re: find value from matrix</title>
      <link>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934114#M210560</link>
      <description>&lt;P&gt;&lt;span class="lia-inline-image-display-wrapper lia-image-align-inline" image-alt="image.png" style="width: 993px;"&gt;&lt;img src="https://www.ptcusercommunity.com/t5/image/serverpage/image-id/99393i3FF7441E949E83C9/image-size/large?v=v2&amp;amp;px=999" role="button" title="image.png" alt="image.png" /&gt;&lt;/span&gt;&lt;/P&gt;</description>
      <pubDate>Sat, 02 Mar 2024 12:42:15 GMT</pubDate>
      <guid>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934114#M210560</guid>
      <dc:creator>ttokoro</dc:creator>
      <dc:date>2024-03-02T12:42:15Z</dc:date>
    </item>
    <item>
      <title>Re: find value from matrix</title>
      <link>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934117#M210561</link>
      <description>&lt;DIV&gt;The input values are z and qcza&lt;/DIV&gt;&lt;DIV&gt;Where z is the depth and qcza is the resistance in each z depth … for example at depth z= 0.2 m the resistance is qcza=3.995 MPa&lt;/DIV&gt;&lt;DIV&gt;d = 0.38 m ..&lt;SPAN&gt;0.7d=0.2 m and 4d = 1.4 m&lt;/SPAN&gt;&lt;/DIV&gt;&lt;DIV&gt;&lt;SPAN&gt;&amp;nbsp;&lt;/SPAN&gt;&lt;/DIV&gt;&lt;DIV&gt;Now q1 is equal to qcza when z is between (0.2&amp;lt;z&amp;lt;1.4)&amp;nbsp;&lt;/DIV&gt;&lt;DIV&gt;&amp;nbsp;&lt;/DIV&gt;&lt;DIV&gt;&amp;nbsp;&lt;/DIV&gt;&lt;DIV&gt;I need to write a program showing the values of q1 as a range&amp;nbsp;&lt;/DIV&gt;&lt;DIV&gt;Considering that q1 should be always small when going deeper .&lt;/DIV&gt;&lt;DIV&gt;For example if qcza is equal to = 7 /8 /6/7/9&amp;nbsp;&lt;/DIV&gt;&lt;DIV&gt;The program should choose q1 as q1= 7/ 7/6/ 6&amp;nbsp;&lt;/DIV&gt;&lt;DIV&gt;Always goes with the smaller number&amp;nbsp;&lt;/DIV&gt;&lt;DIV&gt;I hope you get it&amp;nbsp;&lt;/DIV&gt;</description>
      <pubDate>Sat, 02 Mar 2024 12:57:38 GMT</pubDate>
      <guid>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934117#M210561</guid>
      <dc:creator>YA_10963798</dc:creator>
      <dc:date>2024-03-02T12:57:38Z</dc:date>
    </item>
    <item>
      <title>Re: find value from matrix</title>
      <link>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934118#M210562</link>
      <description>&lt;P&gt;Its a bit lengthier if you also need the the corresponding z-value&lt;/P&gt;
&lt;P&gt;&lt;span class="lia-inline-image-display-wrapper lia-image-align-inline" image-alt="Werner_E_0-1709384167817.png" style="width: 448px;"&gt;&lt;img src="https://www.ptcusercommunity.com/t5/image/serverpage/image-id/99394i393D377A4259E296/image-dimensions/448x310?v=v2" width="448" height="310" role="button" title="Werner_E_0-1709384167817.png" alt="Werner_E_0-1709384167817.png" /&gt;&lt;/span&gt;&lt;/P&gt;
&lt;P&gt;&lt;span class="lia-inline-image-display-wrapper lia-image-align-inline" image-alt="Werner_E_1-1709384219122.png" style="width: 400px;"&gt;&lt;img src="https://www.ptcusercommunity.com/t5/image/serverpage/image-id/99395i78121DC116989520/image-size/medium?v=v2&amp;amp;px=400" role="button" title="Werner_E_1-1709384219122.png" alt="Werner_E_1-1709384219122.png" /&gt;&lt;/span&gt;&lt;/P&gt;
&lt;P&gt;Prime 9 sheet attached&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;</description>
      <pubDate>Sat, 02 Mar 2024 12:57:44 GMT</pubDate>
      <guid>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934118#M210562</guid>
      <dc:creator>Werner_E</dc:creator>
      <dc:date>2024-03-02T12:57:44Z</dc:date>
    </item>
    <item>
      <title>Re: find value from matrix</title>
      <link>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934119#M210563</link>
      <description>&lt;P&gt;Thank you so much I will try it&amp;nbsp;&lt;/P&gt;</description>
      <pubDate>Sat, 02 Mar 2024 12:59:21 GMT</pubDate>
      <guid>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934119#M210563</guid>
      <dc:creator>YA_10963798</dc:creator>
      <dc:date>2024-03-02T12:59:21Z</dc:date>
    </item>
    <item>
      <title>Re: find value from matrix</title>
      <link>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934120#M210564</link>
      <description>&lt;BLOCKQUOTE&gt;&lt;HR /&gt;&lt;a href="https://www.ptcusercommunity.com/t5/user/viewprofilepage/user-id/800166"&gt;@YA_10963798&lt;/a&gt;&amp;nbsp;wrote:&lt;BR /&gt;
&lt;P&gt;Thank you so much I will try it&amp;nbsp;&lt;/P&gt;
&lt;HR /&gt;&lt;/BLOCKQUOTE&gt;
&lt;P&gt;Hope it helps.&lt;/P&gt;
&lt;P&gt;I had not read your second posting (which I have to admit did not understand) when I posted the sheet. So the routine just follows what I had outlined.&lt;/P&gt;</description>
      <pubDate>Sat, 02 Mar 2024 13:11:08 GMT</pubDate>
      <guid>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934120#M210564</guid>
      <dc:creator>Werner_E</dc:creator>
      <dc:date>2024-03-02T13:11:08Z</dc:date>
    </item>
    <item>
      <title>Re: find value from matrix</title>
      <link>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934121#M210565</link>
      <description>&lt;BLOCKQUOTE&gt;&lt;HR /&gt;&lt;a href="https://www.ptcusercommunity.com/t5/user/viewprofilepage/user-id/800166"&gt;@YA_10963798&lt;/a&gt;&amp;nbsp;wrote:&lt;BR /&gt;
&lt;DIV&gt;The input values are z and qcza&lt;/DIV&gt;
&lt;/BLOCKQUOTE&gt;
&lt;P&gt;No! z and qcza are the data vectors for length and pressure (you call it depth and resistance, but I don't care about the meaning of the data).&lt;/P&gt;
&lt;P&gt;The input seems to be a single length/depth Db. You provided 0.4 m as an example&lt;/P&gt;
&lt;P&gt;Its still not clear what the output, the result, should be. I assumed it to be a single pressure value (as described above) but I can't be sure. You did not answer my question if the result of the input value D.b=0,4m really should be 2,22 MPa. If not, what else should the result be and why?&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;BLOCKQUOTE&gt;&lt;HR /&gt;
&lt;DIV&gt;Now q1 is equal to qcza when z is between (0.2&amp;lt;z&amp;lt;1.4)&amp;nbsp;&lt;/DIV&gt;
&lt;DIV&gt;&amp;nbsp;&lt;/DIV&gt;
&lt;/BLOCKQUOTE&gt;
&lt;P&gt;q1? q1 is the desired result, the output. But how could q1 be equal to qcza??? qcza is a vector with 1339 entries!&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;BLOCKQUOTE&gt;&lt;HR /&gt;I need to write a program showing the values of q1 as a range&amp;nbsp;
&lt;DIV&gt;Considering that q1 should be always small when going deeper .&lt;/DIV&gt;
&lt;DIV&gt;For example if qcza is equal to = 7 /8 /6/7/9&amp;nbsp;&lt;/DIV&gt;
&lt;DIV&gt;The program should choose q1 as q1= 7/ 7/6/ 6&amp;nbsp;&lt;/DIV&gt;
&lt;DIV&gt;Always goes with the smaller number&amp;nbsp;&lt;/DIV&gt;
&lt;DIV&gt;I hope you get it&amp;nbsp;&lt;/DIV&gt;
&lt;HR /&gt;&lt;/BLOCKQUOTE&gt;
&lt;P&gt;The leaves me clueless, sorry!&lt;/P&gt;</description>
      <pubDate>Sat, 02 Mar 2024 13:19:00 GMT</pubDate>
      <guid>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934121#M210565</guid>
      <dc:creator>Werner_E</dc:creator>
      <dc:date>2024-03-02T13:19:00Z</dc:date>
    </item>
    <item>
      <title>Re: find value from matrix</title>
      <link>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934123#M210567</link>
      <description>&lt;P&gt;Actually q1 should be also a vector&amp;nbsp;&lt;/P&gt;&lt;P&gt;qcza is group of values in certain depths and I will have to find q1 , q2 and q 3 which are three smaller groups of values in the main group qcza.&amp;nbsp;&lt;/P&gt;&lt;P&gt;q1 is equal&amp;nbsp; qcza in the depth 0.2 and 1.4&amp;nbsp;&lt;/P&gt;&lt;P&gt;and q 2 is equal to qcza in the depth 1.4 and 2.8&amp;nbsp;&lt;/P&gt;&lt;P&gt;However qcza values are random while specifying the range of q1&amp;nbsp; I need the program to choose the smaller values when it goes down in depth z&amp;nbsp;&amp;nbsp;&lt;/P&gt;&lt;DIV&gt;if qcza is equal to = 7 /8 /6/7/9 MPa&lt;/DIV&gt;&lt;DIV&gt;The program should choose q1 as q1= 7/ 7/6/ 6 should not accept higher values&lt;/DIV&gt;&lt;DIV&gt;Always goes with the smaller number&amp;nbsp;&lt;/DIV&gt;</description>
      <pubDate>Sat, 02 Mar 2024 13:31:03 GMT</pubDate>
      <guid>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934123#M210567</guid>
      <dc:creator>YA_10963798</dc:creator>
      <dc:date>2024-03-02T13:31:03Z</dc:date>
    </item>
    <item>
      <title>Re: find value from matrix</title>
      <link>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934124#M210568</link>
      <description>&lt;P&gt;&amp;gt; The program should choose q1 as q1= 7/ 7/6/ 6&amp;nbsp;&lt;/P&gt;
&lt;P&gt;Shouldn't there be a fifth value 6 at the end?&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;You always talk about q1 and now q2, q3 without saying what q2, q3 should be.&lt;/P&gt;
&lt;P&gt;As I understood so far now every input value Db should return a vector of pressure values where each value is either equal or lower than the previous?&lt;/P&gt;
&lt;P&gt;In case thats what you want, - do you also need the corresponding subvector of z-values? Or is all you need the vector q1?&lt;/P&gt;</description>
      <pubDate>Sat, 02 Mar 2024 13:57:44 GMT</pubDate>
      <guid>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934124#M210568</guid>
      <dc:creator>Werner_E</dc:creator>
      <dc:date>2024-03-02T13:57:44Z</dc:date>
    </item>
    <item>
      <title>Re: find value from matrix</title>
      <link>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934126#M210569</link>
      <description>&lt;P&gt;So lets see if this next try comes closer to what you have in mind ...&lt;/P&gt;
&lt;P&gt;&lt;span class="lia-inline-image-display-wrapper lia-image-align-inline" image-alt="Werner_E_0-1709388535593.png" style="width: 999px;"&gt;&lt;img src="https://www.ptcusercommunity.com/t5/image/serverpage/image-id/99396i974708B70BD6E673/image-size/large?v=v2&amp;amp;px=999" role="button" title="Werner_E_0-1709388535593.png" alt="Werner_E_0-1709388535593.png" /&gt;&lt;/span&gt;&lt;/P&gt;
&lt;P&gt;Prime 9 file attached&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;</description>
      <pubDate>Sat, 02 Mar 2024 14:09:42 GMT</pubDate>
      <guid>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934126#M210569</guid>
      <dc:creator>Werner_E</dc:creator>
      <dc:date>2024-03-02T14:09:42Z</dc:date>
    </item>
    <item>
      <title>Re: find value from matrix</title>
      <link>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934128#M210571</link>
      <description>&lt;P&gt;wow that's impressive&amp;nbsp;&lt;/P&gt;&lt;P&gt;I will try it thank you so much for your great help&lt;/P&gt;</description>
      <pubDate>Sat, 02 Mar 2024 14:13:09 GMT</pubDate>
      <guid>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934128#M210571</guid>
      <dc:creator>YA_10963798</dc:creator>
      <dc:date>2024-03-02T14:13:09Z</dc:date>
    </item>
    <item>
      <title>Re: find value from matrix</title>
      <link>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934140#M210579</link>
      <description>&lt;P&gt;it works thank you so much. I made some changes but your solution was impressive. If you have time you should have a Youtube channel you are a great teacher . Once again thank you&amp;nbsp;&lt;/P&gt;</description>
      <pubDate>Sat, 02 Mar 2024 19:31:16 GMT</pubDate>
      <guid>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934140#M210579</guid>
      <dc:creator>YA_10963798</dc:creator>
      <dc:date>2024-03-02T19:31:16Z</dc:date>
    </item>
    <item>
      <title>Re: find value from matrix</title>
      <link>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934142#M210580</link>
      <description>&lt;P&gt;If you feel uncomfortable with using "match" and "submatrix", here is a version which may be clearer to read and follow. The result is the same of course&lt;/P&gt;
&lt;P&gt;&lt;span class="lia-inline-image-display-wrapper lia-image-align-inline" image-alt="Werner_E_0-1709408994520.png" style="width: 421px;"&gt;&lt;img src="https://www.ptcusercommunity.com/t5/image/serverpage/image-id/99401i6383C0E73CCC32BB/image-dimensions/421x569?v=v2" width="421" height="569" role="button" title="Werner_E_0-1709408994520.png" alt="Werner_E_0-1709408994520.png" /&gt;&lt;/span&gt;&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;</description>
      <pubDate>Sat, 02 Mar 2024 19:51:19 GMT</pubDate>
      <guid>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934142#M210580</guid>
      <dc:creator>Werner_E</dc:creator>
      <dc:date>2024-03-02T19:51:19Z</dc:date>
    </item>
    <item>
      <title>Re: find value from matrix</title>
      <link>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934145#M210581</link>
      <description>&lt;DIV&gt;&lt;DIV&gt;The input values are z and qcza&lt;/DIV&gt;&lt;DIV&gt;Where z is the depth and qcza is the resistance in each z depth … for example at depth z= 0.2 m the resistance is qcza=3.995 MPa&lt;/DIV&gt;&lt;DIV&gt;d = 0.38 m .. &lt;SPAN&gt;0.7d=0.2 m and 4d = 1.4 m&lt;/SPAN&gt;&lt;/DIV&gt;&lt;DIV&gt;&lt;SPAN&gt;&lt;BR /&gt;&lt;/SPAN&gt;&lt;/DIV&gt;&lt;DIV&gt;Now q1 is equal to qcza when z is between (0.2&amp;lt;z&amp;lt;1.4)&lt;/DIV&gt;&lt;DIV&gt;&lt;BR /&gt;&lt;/DIV&gt;&lt;/DIV&gt;&lt;DIV&gt;I need to write a program showing the values of q1&lt;/DIV&gt;&lt;DIV&gt;Considering that q1 should be always small when going deeper .&lt;/DIV&gt;&lt;DIV&gt;For example if qcza is equal to = 7 , 8,6,7,9&lt;/DIV&gt;&lt;DIV&gt;The program should choose q1 as q1= 7, 7, 6, 6&lt;/DIV&gt;&lt;DIV&gt;Always goes with the smaller number&lt;/DIV&gt;&lt;DIV&gt;I hope you get it&lt;/DIV&gt;&lt;DIV&gt;&lt;BR /&gt;&lt;/DIV&gt;</description>
      <pubDate>Sun, 03 Mar 2024 01:30:17 GMT</pubDate>
      <guid>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934145#M210581</guid>
      <dc:creator>YA_10963798</dc:creator>
      <dc:date>2024-03-03T01:30:17Z</dc:date>
    </item>
    <item>
      <title>Re: find value from matrix</title>
      <link>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934147#M210582</link>
      <description>&lt;P&gt;&lt;span class="lia-inline-image-display-wrapper lia-image-align-inline" image-alt="image.png" style="width: 999px;"&gt;&lt;img src="https://www.ptcusercommunity.com/t5/image/serverpage/image-id/99402iF86E49DE506C85C3/image-size/large?v=v2&amp;amp;px=999" role="button" title="image.png" alt="image.png" /&gt;&lt;/span&gt;&lt;/P&gt;</description>
      <pubDate>Sun, 03 Mar 2024 01:57:33 GMT</pubDate>
      <guid>https://www.ptcusercommunity.com/t5/Mathcad/find-value-from-matrix/m-p/934147#M210582</guid>
      <dc:creator>ttokoro</dc:creator>
      <dc:date>2024-03-03T01:57:33Z</dc:date>
    </item>
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