topic Re: Pro-Program IF statement question in 3D Part & Assembly Design

Pro-Program IF statement question

Steve99 — Thu, 02 Jul 2020 15:54:58 GMT

Hello,

Looking for help with Pro-Program IF statement. I have a part model that has 2 different bolt hole patterns. I would like to turn off or suppress the larger bolt pattern when the diameter is below a certain size. For instance;

If diameter d37 <= 5.500, turn off or suppress pattern 2, else leave pattern 2.

I greatly appreciate the help,

Steve

Re: Pro-Program IF statement question

avero — Fri, 03 Jul 2020 05:13:25 GMT

First you should create a real number parameter called something like PART_DIAMETER and attach it to the diameter using relations. In relations you would either type PART_DIAMETER=dxxx or dxxx=PART_DIAMETER (you will find the dxxx value by clicking on the extrude sketch while in relations), depending on whether you want to control the diameter by changing the parameter or have the parameter change based on whatever value you put in the extrude sketch.

After that you open Pro-Program, locate the larger bolt hole pattern and type IF PART_DIAMETER<=5500 right before the ADD FEATURE (initial number xx) text that Creo has generated. Finally you locate END ADD and type in END IF after that. Make sure you get both the hole and the pattern you want to suppress in between the IF statement and END IF.

It should look something like this:

IF PART_DIAMETER<=5500

ADD FEATURE (initial number xx)

feature ID, parents, dimensions etc.

END ADD

END IF

Re: Pro-Program IF statement question

MartinHanak — Fri, 03 Jul 2020 05:29:49 GMT

Hi,

it is not necessary to create a parameter.

1.] user can use IF dxxx<=5500 notation

2.] user can rename dimension symbol from dxxx to PART_DIAMETER and use IF PART_DIAMETER<=5500 notation

Re: Pro-Program IF statement question

avero — Fri, 03 Jul 2020 05:53:25 GMT

Ok, then I learned something myself, thanks!

Re: Pro-Program IF statement question

HamsterNL — Fri, 03 Jul 2020 06:45:05 GMT

Although creating a parameter is not necessary, I would recommend to do it anyway

Why?

If you are putting your logic into the PRO/Program, a user needs to have an AAX license to change/overrule that logic... Sooner of later, a user will have the need to overrule your logic.

So we would create a new parameter SHOW_PATTERN in the RELATIONS:

IF PART_DIAMETER <= 5500

SHOW_PATTERN = NO

ELSE

SHOW_PATTERN = YES

ENDIF

Or, if you would like to shorten your code in your RELATIONS:

SHOW_PATTERN = (PART_DIAMETER > 5500)

Then, you can use the SHOW_PATTERN parameter in the PRO/Program:

IF SHOW_PATTERN

ADD FEATURE (xxx)

...

END ADD

ENDIF

Now if a user want to overrule the logic, he can either change the value 5500 to something else, or he could simply write SHOW_PATTERN = YES just below the logic.

Re: Pro-Program IF statement question

LukaszMazur — Tue, 07 Jul 2020 06:09:59 GMT

@HamsterNL wrote:

If you are putting your logic into the PRO/Program, a user needs to have an AAX license to change/overrule that logic... Sooner of later, a user will have the need to overrule your logic.

As far as I know, AAX license is needed only if you're using Pro/PROGRAM at the assembly level; if you use it in single part, it should be covered by the base license. So it all depends on where you need to actually work with Pro/PROGRAM.

Re: Pro-Program IF statement question

HamsterNL — Tue, 07 Jul 2020 07:08:04 GMT

That's true...editing the PRO/Program of an Assembly requires an AAX license.

Re: Pro-Program IF statement question

Steve99 — Wed, 22 Jul 2020 11:18:46 GMT

Worked perfectly for what I needed. Thank you all so much for the responses