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1i*ln(1/[e^pi]^1i) simplify ==> -pi and 1i*ln(1/[e^pi]^1i) = -pi simplify ==> 0 ( Could apply "simplify" in this case ? )

lvl107
20-Turquoise

1i*ln(1/[e^pi]^1i) simplify ==> -pi and 1i*ln(1/[e^pi]^1i) = -pi simplify ==> 0 ( Could apply "simplify" in this case ? )

   Hello Everyone.

simplify.PNG

   1i*ln(1/[e^pi]^1i) simplify ==> -pi  and  1i*ln(1/[e^pi]^1i) = -pi simplify ==> 0 ( Could apply "simplify" in this case ? )

           Thanks in advance.

                 Regards.

1 REPLY 1
-MFra-
21-Topaz II
(To:lvl107)

Hi Loi Le,

Okay so?

imageFile.png

imageFile.jpg

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